array

[Anonymous]

why cannot show the picture using this method?
got another way to do it?
thanks...

<? 
mysql_select_db($dbname, $link);
$result=mysql_query("select * from user_detail where nickname = '$name'") ;
$number_of_array = mysql_num_rows($result);
while ($number_of_array = mysql_fetch_array($result)){
echo"<img src=\"./image/$number_of_array[image_name]\">";
}				
?>

 

[gesf]

This this:

echo "<img src=\"./image/" . $number_of_array[image_name] . "\">";

Or better yet:

echo '<img src="./image/' . $number_of_array['image_name'] . '">';

 

[Anonymous]

i've tried all the possible ways to do that, but can't....

it just shows this when i check the properties of the picture, without the "william.jpg"

http://localhost/image/

 

[gesf]

Try to link to the image like:

echo '<img src="image/' . $number_of_array['image_name'] . '">';

BTW, make sure it´s everything alright with the file name: echo $number_of_array['image_name'];