fopen()

[Anonymous]

i have something like this now:

$h = fopen("url?name=mine","r");
if($h){
execute some code...
}

but i still get a warning in the output file if fopen fails to connect to the url.

my question is is there a way to catch the error so it doesnt display in the output file?

 

[Anonymous]

use @ before the fopen() i.e. @fopen()

 

[Anonymous]

ahhhh.... yes.... lol, now that i think about it, I dont know why i didnt figure that out myself, since I use it when selecting a mysql table.... .... thanks!