statement inside array

A

Anonymous

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Code: 
while ($number_of_array = mysql_fetch_array($query)) {

	echo "<TD><a href=viewuser.php?name=$number_of_array[nickname] target=_blank>$number_of_array[nickname]</a></TD>\n";	
	echo "<TD>$number_of_array[gender]</TD>\n"; 
	echo "<TD>$age</TD>\n"; 
	echo "<TD>$number_of_array[location]</TD>\n"; 
	echo "<TD>$number_of_array[country]</TD>\n"; 
}

can i put the if else statement or while loop behind:
<a href=viewuser.php?name=$number_of_array[nickname] target=_blank>$number_of_array[nickname]</a>

if the value is equal to 1, then echo a picture

something like the picture attached...

pic.jpg


i've tried, but got error...

thanks.
 
Could you rephrase your question? If you just want to show an image if a particular condition is true, then test for that condition (with if) and if it's true, output the code for the image, and if not, don't.
 
in my table has 1 column named "image", default is 0.
when i upload the picture, the 0 will set to 1.
then check the value, if the value is equal to 1, then show the camera.gif
this is what i meaned...
 
Okay, so have an if statement that checks whether it's set to 1. If it is, display the image. If it isn't, don't.
 
Code: 
while ($number_of_array = mysql_fetch_array($query)) {
    echo "<td>";
   if($number_of_array['image']) echo $number_of_array['image_name'];
   echo '</td>';
   echo "<TD><a href=viewuser.php?name=$number_of_array[nickname] target=_blank>$number_of_array[nickname]</a></TD>\n";   
   echo "<TD>$number_of_array[gender]</TD>\n";
   echo "<TD>$age</TD>\n";
   echo "<TD>$number_of_array[location]</TD>\n";
   echo "<TD>$number_of_array[country]</TD>\n";
}

That what you mean?
 
Do you want me to hold your hand while doing this?

I gave you an idea on how to do it.. you will have to tweak it to your liking
 
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